Converting Celsius to Fahrenheit with Python

Here's a useful mnemonic for remembering how to convert Celsius to Fahrenhait(*):

• Start at 4°C
• Add +12 each time
• Flip the C in mirror, with some additional fudging

For example, 4°C is 04°C. Mirror image of "04" is "40". So 4°C equals 40°F.
And when there's a 1 in front, as in 125°F, look at that as 100 + 25°F. Mirror of 25°F is 52°C. So 52°C equals 125°F.

In Python it can be tested like this:

import math


def c2f(c):
    return c * 9 / 5 + 32


def is_mirror(a, b):
    def massage(n):
        if n < 10:
            return f"0{n}"
        elif n >= 100:
            return massage(n - 100)
        else:
            return str(n)

    return massage(a)[::-1] == massage(b)


def print_conv(c, f):
    print(f"{c}°C ~= {f}°F")


for i in range(4, 100, 12):
    f = c2f(i)
    if is_mirror(i, math.ceil(f)):
        print_conv(i, math.ceil(f))
    elif is_mirror(i, math.floor(f)):
        print_conv(i, math.floor(f))
    else:
        break

When you run that you get:

4°C ~= 40°F
16°C ~= 61°F
28°C ~= 82°F
40°C ~= 104°F
52°C ~= 125°F

(*) If you can't remember F = C × 9/5 + 32 or, perhaps, remember it but can't compute the arithmetic easily.